Windows 7 
Access 2010 (version 14.0)
Hi,
Firstly - very novice at programming using VB - I tend to search the net for code, and try to amend it to what I want to do - sometimes successfully.
I have an existing Access Database that has a series of buttons. I am trying to code one of the buttons, so that on click it will open (not import) an existing file - by allowing the user to select the file, and in this case, excel (but not necessarily limited to excel). I have found the following code, but it's not working, giving me a compile error at the very first dim statement. Can anybody point out to me where I am going wrong, or suggest an alternative method to what I am trying to do? Thanks in advance.
Private Sub FeesPaid_Click()
'Declare a variable as a FileDialog object.
Dim fd As FileDialog
'Create a FileDialog object as a File Picker dialog box.
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'Declare a variable to contain the path
'of each selected item. Even though the path is a String,
'the variable must be a Variant because For Each...Next
'routines only work with Variants and Objects.
Dim vrtSelectedItem As Variant
'Use a With...End With block to reference the FileDialog object.
With fd
'Use the Show method to display the File Picker dialog box and return the user's action.
'The user pressed the action button.
If .Show = -1 Then
'Step through each string in the FileDialogSelectedItems collection.
For Each vrtSelectedItem In .SelectedItems
'vrtSelectedItem is a String that contains the path of each selected item.
'You can use any file I/O functions that you want to work with this path.
'This example simply displays the path in a message box.
MsgBox "The path is: " & vrtSelectedItem
Next vrtSelectedItem
'The user pressed Cancel.
Else
End If
End With
'Set the object variable to Nothing.
Set fd = Nothing
End Sub
Reply With Quote
