Convert numbers to words WITH negatives

[Alexandre Cote]

I have tailored some code on the internet to make it work to my needs. I have read that it is fairly simple to tailor the code to make it handle negatives. Could someone help me out? I am having trouble making it work. Here is code that works perfectly, but only for positive numbers:

Function SpellNumber(ByVal MyNumber)
    Dim point, percent, Temp
    Dim DecimalPlace, Count
 
    ReDim Place(9) As String
    Place(2) = " Thousand "
    Place(3) = " Million "
    Place(4) = " Billion "
    Place(5) = " Trillion "
 
    ' String representation of amount
    MyNumber = Trim(Str(MyNumber))
 
    ' Position of decimal place 0 if none
    DecimalPlace = InStr(MyNumber, ".")
    'Convert percent and set MyNumber to dollar amount
    If DecimalPlace > 0 Then
        percent = GetTens(Left(Mid(MyNumber, DecimalPlace + 1) & "00", 2))
        MyNumber = Trim(Left(MyNumber, DecimalPlace - 1))
    End If
 
    Count = 1
    Do While MyNumber <> ""
       Temp = GetHundreds(Right(MyNumber, 3))
       If Temp <> "" Then point = Temp & Place(Count) & point
          If Len(MyNumber) > 3 Then
             MyNumber = Left(MyNumber, Len(MyNumber) - 3)
        Else
            MyNumber = ""
        End If
        Count = Count + 1
    Loop
 
    Select Case point
        Case ""
            point = "zero point"
        Case "One"
            point = "one percent"
        Case Else
            point = point & "point"
    End Select
 
    Select Case percent
        Case ""
            percent = " zero percent"
        Case "One"
            percent = " one percent"
        Case Else
            percent = " " & percent & "percent"
    End Select
 
    SpellNumber = point & percent
End Function
 
'*******************************************
' Converts a number from 100-999 into text *
'*******************************************
Function GetHundreds(ByVal MyNumber)
    Dim Result As String
 
    If Val(MyNumber) = 0 Then Exit Function
    MyNumber = Right("000" & MyNumber, 3)
 
    'Convert the hundreds place
    If Mid(MyNumber, 1, 1) <> "0" Then
        Result = GetDigit(Mid(MyNumber, 1, 1)) & " Hundred "
    End If
 
    'Convert the tens and ones place
    If Mid(MyNumber, 2, 1) <> "0" Then
        Result = Result & GetTens(Mid(MyNumber, 2))
    Else
        Result = Result & GetDigit(Mid(MyNumber, 3))
    End If
 
    GetHundreds = Result
End Function
 


'*********************************************
' Converts a number from 10 to 99 into text. *
'*********************************************
Function GetTens(TensText)
    Dim Result As String
 
    Result = ""           'null out the temporary function value
    If Val(Left(TensText, 1)) = 1 Then   ' If value between 10-19
        Select Case Val(TensText)
            Case 10: Result = "ten "
            Case 11: Result = "eleven "
            Case 12: Result = "twelve "
            Case 13: Result = "thirteen "
            Case 14: Result = "fourteen "
            Case 15: Result = "fifteen "
            Case 16: Result = "sixteen "
            Case 17: Result = "seventeen "
            Case 18: Result = "eighteen "
            Case 19: Result = "nineteen "
            Case Else
        End Select
      Else                                 ' If value between 20-99
        Select Case Val(Left(TensText, 1))
            Case 2: Result = "twenty "
            Case 3: Result = "thirty "
            Case 4: Result = "forty "
            Case 5: Result = "fifty "
            Case 6: Result = "sixty "
            Case 7: Result = "seventy "
            Case 8: Result = "eighty "
            Case 9: Result = "ninety "
            Case Else
        End Select
         Result = Result & GetDigit _
            (Right(TensText, 1))  'Retrieve ones place
      End If
      GetTens = Result
   End Function
 
'*******************************************
' Converts a number from 1 to 9 into text. *
'*******************************************
Function GetDigit(Digit)
    Select Case Val(Digit)
        Case 1: GetDigit = "one "
        Case 2: GetDigit = "two "
        Case 3: GetDigit = "three "
        Case 4: GetDigit = "four "
        Case 5: GetDigit = "five "
        Case 6: GetDigit = "six "
        Case 7: GetDigit = "seven "
        Case 8: GetDigit = "eight "
        Case 9: GetDigit = "nine "
        Case Else: GetDigit = ""
    End Select
End Function 

Thanks in advance

[cowboy]

What does it do when you put in a negative number?

[FogLine]

Hey Alexandre see if this code will help you any.


' Convert a currency value into an (American) English string
Function English (ByVal N As Currency) As String
Const Thousand = 1000@
Const Million = Thousand * Thousand
Const Billion = Thousand * Million
Const Trillion = Thousand * Billion
If (N = 0@) Then English = "zero": Exit Function
Dim Buf As String: If (N < 0@) Then Buf = "negative " Else Buf = ""
Dim Frac As Currency: Frac = Abs(N - Fix(N))
If (N < 0@ Or Frac <> 0@) Then N = Abs(Fix(N))
Dim AtLeastOne As Integer: AtLeastOne = N >= 1
If (N >= Trillion) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(Int(N / Trillion)) & " trillion"
N = N - Int(N / Trillion) * Trillion ' Mod overflows
If (N >= 1@) Then Buf = Buf & " "
End If

If (N >= Billion) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(Int(N / Billion)) & " billion"
N = N - Int(N / Billion) * Billion ' Mod still overflows
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= Million) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N \ Million) & " million"
N = N Mod Million
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= Thousand) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N \ Thousand) & " thousand"
N = N Mod Thousand
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= 1@) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N)
End If
If (Frac = 0@) Then
Buf = Buf & " exactly"
ElseIf (Int(Frac * 100@) = Frac * 100@) Then
If AtLeastOne Then Buf = Buf & " and "
Buf = Buf & Format$(Frac * 100@, "00") & "/100"
Else
If AtLeastOne Then Buf = Buf & " and "
Buf = Buf & Format$(Frac * 10000@, "0000") & "/10000"
End If
English = Buf
End Function



' Support function to be used only by English()
Private Function EnglishDigitGroup (ByVal N As Integer) As String
Const Hundred = " hundred"
Const One = "one"
Const Two = "two"
Const Three = "three"
Const Four = "four"
Const Five = "five"
Const Six = "six"
Const Seven = "seven"
Const Eight = "eight"
Const Nine = "nine"
Dim Buf As String: Buf = ""
Dim Flag As Integer: Flag = False
'Do hundreds
Select Case (N \ 100)
Case 0: Buf = "": Flag = False
Case 1: Buf = One & Hundred: Flag = True
Case 2: Buf = Two & Hundred: Flag = True
Case 3: Buf = Three & Hundred: Flag = True
Case 4: Buf = Four & Hundred: Flag = True
Case 5: Buf = Five & Hundred: Flag = True
Case 6: Buf = Six & Hundred: Flag = True
Case 7: Buf = Seven & Hundred: Flag = True
Case 8: Buf = Eight & Hundred: Flag = True
Case 9: Buf = Nine & Hundred: Flag = True
End Select

If (Flag <> False) Then N = N Mod 100
If (N > 0) Then
If (Flag <> False) Then Buf = Buf & " "
Else
EnglishDigitGroup = Buf
Exit Function
End If

'Do tens (except teens)
Select Case (N \ 10)
Case 0, 1: Flag = False
Case 2: Buf = Buf & "twenty": Flag = True
Case 3: Buf = Buf & "thirty": Flag = True
Case 4: Buf = Buf & "forty": Flag = True
Case 5: Buf = Buf & "fifty": Flag = True
Case 6: Buf = Buf & "sixty": Flag = True
Case 7: Buf = Buf & "seventy": Flag = True
Case 8: Buf = Buf & "eighty": Flag = True
Case 9: Buf = Buf & "ninety": Flag = True
End Select

If (Flag <> False) Then N = N Mod 10
If (N > 0) Then
If (Flag <> False) Then Buf = Buf & "-"
Else
EnglishDigitGroup = Buf
Exit Function
End If

'Do ones and teens
Select Case (N)
Case 0: ' do nothing
Case 1: Buf = Buf & One
Case 2: Buf = Buf & Two
Case 3: Buf = Buf & Three
Case 4: Buf = Buf & Four
Case 5: Buf = Buf & Five
Case 6: Buf = Buf & Six
Case 7: Buf = Buf & Seven
Case 8: Buf = Buf & Eight
Case 9: Buf = Buf & Nine
Case 10: Buf = Buf & "ten"
Case 11: Buf = Buf & "eleven"
Case 12: Buf = Buf & "twelve"
Case 13: Buf = Buf & "thirteen"
Case 14: Buf = Buf & "fourteen"
Case 15: Buf = Buf & "fifteen"
Case 16: Buf = Buf & "sixteen"
Case 17: Buf = Buf & "seventeen"
Case 18: Buf = Buf & "eighteen"
Case 19: Buf = Buf & "nineteen"
End Select
EnglishDigitGroup = Buf
End Function
'************ Code End **********