Hello,
What's the formula we can use to calculate days between no of days between date job is open and today's date in a query. I am using formulat below formula but the DATE_OPEN and Today (todays date) pops us as enter parameter value. I dont want those enter parameter windows pops us. The date job is open is in a linked table and linked table is getting the information from BPCS software. The date in Liinked is in format YYYYMMDD. Please help
Total Days: DateDiff("d",[Date_Open],[Today])
The SQL Details are below. AUNPRDF_AAA802 is a linked table and information gets updated on 12 am everyday
SELECT DateDiff("d",[Date_Open],[Today]) AS [Total Days], AUNPRDF_AAA802.AAAGE AS Age, AUNPRDF_AAA802.AAORD AS [Job Number], AUNPRDF_AAA802.AAWKSP AS Workshop, AUNPRDF_AAA802.AASWKT AS WorkType, AUNPRDF_AAA802.AANAME AS [Customer Name], AUNPRDF_AAA802.AANME AS [Service Admin], AUNPRDF_AAA802.AASDE1 AS Complaint, AUNPRDF_AAA802.AASDE2 AS Cause, AUNPRDF_AAA802.AASDE3 AS Correction, Sum(AUNPRDF_AAA802.AATOT) AS Total, CDate(Right([AAODTE],2) & "/" & Mid([AAODTE],5,2) & "/" & Left([AAODTE],4)) AS Date_Open, Date() AS Today
FROM AUNPRDF_AAA802
GROUP BY DateDiff("d",[Date_Open],[Today]), AUNPRDF_AAA802.AAAGE, AUNPRDF_AAA802.AAORD, AUNPRDF_AAA802.AAWKSP, AUNPRDF_AAA802.AASWKT, AUNPRDF_AAA802.AANAME, AUNPRDF_AAA802.AANME, AUNPRDF_AAA802.AASDE1, AUNPRDF_AAA802.AASDE2, AUNPRDF_AAA802.AASDE3, CDate(Right([AAODTE],2) & "/" & Mid([AAODTE],5,2) & "/" & Left([AAODTE],4)), Date(), AUNPRDF_AAA802.AARTYP
HAVING (((AUNPRDF_AAA802.AARTYP)="1"));
Thanks