Summing half a value with full value on an IF

[Ruegen]

I'm using Totals: Sum(IIf([ShowTime1st]>0,1,0)+IIf([ShowTime2nd]>0,1,0)+IIf([ShowTime3rd]>0,1,0)+IIf([ShowTime4th]>0,1,0)+IIf([ShowTime5th]>0,1,0)) to sum totals in a query and it works great, however I have been told that if the school is SchoolType 3 then it gets a half value (.5) for each ShowTime

I can't figure out how to sum those that aren't 3 with those with 3. So if a few of the schools are type 3 then they get added to the total but as .5

[Ruegen]

i have tried

Totals: Sum(IIf([SchoolTypeID = 3, IIf([ShowTime1st]>0,1/2,0)+IIf([ShowTime2nd]>0,1/2,0)+IIf([ShowTime3rd]>0,1/2,0)+IIf([ShowTime4th]>0,1/2,0)+IIf([ShowTime5th]>0,1/2,0),IIf([ShowTime1st]>0,1,0)+IIf([ShowTime2nd]>0,1,0)+IIf([ShowTime3rd]>0,1,0)+IIf([ShowTime4th]>0,1,0)+IIf([ShowTime5tIIf([ShowTime1st]>0,1,0)+IIf([ShowTime2nd]>0,1,0)+IIf([ShowTime3rd]>0,1,0)+IIf([ShowTime4th]>0,1,0)+IIf([ShowTime5th]>0,1,0)]>0,1,0)))

with no luck, even placing .5 has problems

[Ruegen]

eh I had missed the closing of SchoolTypeID and went with this

Totals: Sum(IIf([tblSchools]![SchoolTypeID]=3,IIf([ShowTime1st]>0,0.5,0)+IIf([ShowTime2nd]>0,0.5,0)+IIf([ShowTime3rd]>0,0.5,0)+IIf([ShowTime4th]>0,0.5,0)+IIf([ShowTime5th]>0,0.5,0),IIf([ShowTime1st]>0,1,0)+IIf([ShowTime2nd]>0,1,0)+IIf([ShowTime3rd]>0,1,0)+IIf([ShowTime4th]>0,1,0)+IIf([ShowTime5th]>0,1,0)))

[Ruegen]

update - was getting wrong results from someone else to compare to.