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  1. #1
    rshaw63 is offline Advanced Beginner
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    Can Someone help me with this one please !!! Banging Head On Keyboard

    Greetings everyone.

    I have a form with a couple of text boxes bound with the following

    =IIf([TEST1_Compaction]=[Project_Spec]+[Spec_Allowence_Compaction] Or [TEST1_Compaction]=[Project_Spec]-[Spec_Allowence_Compaction],"Pass","Fail")

    what needs to happen is if the TEST1_compaction field equals the project spec within the range per say +/- 3% then it needs to say pass otherwise fail.



    i am pretty sure that the above is saying either 3 above or 3 below but not the range in between. Am i correct or does someone know what it needs to say to pass as long as Test1 COmpaction is within the range

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  2. #2
    kd2017 is offline Well, I tried at least.
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    =IIf(abs([Project_Spec] - [TEST1_Compaction]) <= [Spec_Allowence_Compaction], "pass", "fail")

  3. #3
    Micron is offline Virtually Inert Person
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    I could be wrong but I'd say that solution will only provide one value, not a range.
    maybe
    =IIf([TEST1_Compaction]<=[Project_Spec]+[Spec_Allowence_Compaction] AND [TEST1_Compaction]>=[Project_Spec]-[Spec_Allowence_Compaction],"Pass","Fail") ?

    Hard for me to say because I see no form field called Project_Spec but if I use Compaction_Spec I get a range of 95.2 to 100.8 which is a fail in this case.
    The more we hear silence, the more we begin to think about our value in this universe.
    Paraphrase of Professor Brian Cox.

  4. #4
    kd2017 is offline Well, I tried at least.
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    Quote Originally Posted by Micron View Post
    I could be wrong but I'd say that solution will only provide one value, not a range.
    It compares the absolute value of the delta to the allowance.

    It works in my test. The thing to be weary of us floating point rounding errors. One way to get around that would be to round both sides of the equation like this
    Code:
    =IIf(Round(Abs([Project_Spec]-[TEST1_Compaction]),6)<=Round([Spec_Allowence_Compaction],6),"pass","fail")
    I rounded (round, rounded?? I no speak gud) to 6 decimal places, I don't know what kind of precision is required.

  5. #5
    Micron is offline Virtually Inert Person
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    It compares the absolute value of the delta to the allowance.
    I could see that you were using the absolute value but it didn't sink in before coffee. I have remedied that now but think I should have caught on right away because I swear I've used that before. It works because the high and low is the same deviation value.
    Nice one!
    The more we hear silence, the more we begin to think about our value in this universe.
    Paraphrase of Professor Brian Cox.

  6. #6
    rshaw63 is offline Advanced Beginner
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    thank you all for the responses

    I think the AND is a definite need in this case because both conditions must be true to be a pass so if i understand the language correctly if say the project spec is between 93 and 97 it should say pass correct? im not sure whether KD2017 response would compare both but i am not that good at understanding. I know what i want it to do lol just not sure how to make it do it.

  7. #7
    kd2017 is offline Well, I tried at least.
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    Quote Originally Posted by rshaw63 View Post
    thank you all for the responses

    I think the AND is a definite need in this case because both conditions must be true to be a pass so if i understand the language correctly if say the project spec is between 93 and 97 it should say pass correct? im not sure whether KD2017 response would compare both but i am not that good at understanding. I know what i want it to do lol just not sure how to make it do it.
    Either approach will work. I'll try to illustrate my equation for understanding's sake:

    =IIf(abs([Project_Spec] - [TEST1_Compaction]) <= [Spec_Allowence_Compaction], "pass", "fail")
    abs() is the absolute value function

    given:
    spec = 95.0
    test_1 = 93.0
    test_2 = 97.0
    allowance = +-3.0

    Abs( spec - test_1 ) <= allowance
    Abs( 95.0 - 93.0 ) = Abs( 2.0 ) = 2.0 <= 3.0 Pass

    Abs( spec - test_2 ) <= allowance
    Abs( 95.0 - 97.0 ) = Abs( -2.0 ) = 2.0 <= 3.0 Pass

    For input validation you may want to ensure the user can't accidentally input negative numbers into the allowance fields.

    It's worth mentioning again, doing comparisons on floating point number (single, double datatypes) can give funny results due to rounding errors. My initial thought per post #4 was to use the round function like so but I'm not sure if it's a bullet proof solution... Hopefully others can chime in on this
    Code:
    =IIf(Round(Abs([Project_Spec]-[TEST1_Compaction]),6)<=Round([Spec_Allowence_Compaction],6),"pass","fail")

  8. #8
    rshaw63 is offline Advanced Beginner
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    thank you for the great explanation and your time. all is working as it should now thank you everyone

  9. #9
    rshaw63 is offline Advanced Beginner
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    okay this is simple i am sure KD2017 when i changed the box to your code i get a " #NAME?" error inside the box now any ideas>?

  10. #10
    kd2017 is offline Well, I tried at least.
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    That just means something is spelled wrong in the equation. Make sure all the names match up letter for letter with their corresponding field or form control. If it's still an issue you can upload a zipped copy of your db for review.

  11. #11
    rshaw63 is offline Advanced Beginner
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    thanks man but that db is already about 500megs in size

  12. #12
    rshaw63 is offline Advanced Beginner
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    okay figured that one out thanks again man have a great weekend.

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