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  1. #1
    Thompyt is offline Expert
    Windows 8 Access 2010 32bit
    Join Date
    Sep 2014
    El Paso, TX

    Compare Numbers in Different rows to for highest and lowest value

    I have made it this far

    Attached is the output of a query.

    Using 117Dual query to find the parent_ID values of the Mount, the radio, Channels 1 and 2.

    How do I compare the values of the unique_id assigned to a parent_equipment_item_id? First one is to assign the first radio which has the lower unique-id, and the second to the higher of the 2. There are 2 radios assigned to the mount.

    After we get the unique_id of the lower value we can use that to repeat the process for the channels

    Click image for larger version. 

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    In the above pic the first column is the primary unique_id we start off from. Using that number, we look in the parent_equipment_item_id where the Equip LIN column is a certain value shown in the Green box. There should be 2 assigned.
    How do I determine the lower value of the two in the green box?


  2. #2
    ranman256's Avatar
    ranman256 is offline VIP
    Windows Vista Access 2010 32bit
    Join Date
    Apr 2014
    can you just create a 'Find Duplicate' query?
    Use the query wizard , and make the 'Find Duplicate':

    SELECT Data.[parent_equipment_item_id], Data.[ID], Data.[Equip LIN], Data.[unique_id]
    FROM Data
    WHERE (((Data.[parent_equipment_item_id]) In (SELECT [parent_equipment_item_id] FROM [Data] As Tmp GROUP BY [parent_equipment_item_id] HAVING Count(*)>1 )))
    ORDER BY Data.[parent_equipment_item_id];

    and if you already have a UNIQUE_ID field, why do you have an autonumber field too?

  3. #3
    Thompyt is offline Expert
    Windows 8 Access 2010 32bit
    Join Date
    Sep 2014
    El Paso, TX
    Good point on id as extraneous, once done troubleshooting, I will take it out and use unique_id as the link.

    I see what you did with the query, but I still need to use which is lesser to determine which is gadget 1.

    Click image for larger version. 

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ID:	31830

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