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  1. #1
    jwill is offline Advanced Beginner
    Windows Vista Access 2010 64bit
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    Need help calculating time on my report

    I think I made have a design flaw. Trying to calculate time on a report for my employee log in/log out table. This is my table

    staff_log_empl_num text
    staff_log_date date/time


    time_in_time_out text "time in" or "time out"
    staff_log_time date/time

    I may not have designed the table correctly. I'm trying to create a form that calculates the hours worked per employee, per day, per week. A pic of my report is attached. Do I need to redesign the table or can I do something w/ the way it is?

    doc1.pdf

  2. #2
    June7's Avatar
    June7 is online now VIP
    Windows XP Access 2010 32bit
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    Your data is normalized but calculating values of sequential records can be difficult. Requires subqueries. For one method, see the example 'Get the value in another record' at http://allenbrowne.com/subquery-01.html

    Your situation is complicated because you want to calculate daily and weekly totals, not just a month cut-off date.

    Is there only one In/Out pair per day? Try doing a query for the Ins and a query for the Outs, in another query join them on the date. This will get the In and Out pairs in a single record and can calculate the difference. The text time values will have to be converted to a date/time value to do a DateDiff calculation.

    SELECT LogDate, LogTime, LogDate & " " & LogTime As LogDateTime WHERE LogInOut = "IN";
    SELECT LogDate, LogTime, LogDate & " " & LogTime As LogDateTime WHERE LogInOut = "OUT";

    Use DatePart to extract a week number that can be used as grouping criteria in summary calcs: DatePart("ww", LogDate)
    How to attach file: http://www.accessforums.net/showthread.php?t=70301 To provide db: copy, remove confidential data, run compact & repair, zip w/Windows Compression.

  3. #3
    jwill is offline Advanced Beginner
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    Thanks June7 I'll take a look at the article

  4. #4
    jwill is offline Advanced Beginner
    Windows Vista Access 2010 64bit
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    I've decided to change the structure of the table. Lesson learned . I will make the time in and time out all the same record. Thanks for the response.

  5. #5
    jwill is offline Advanced Beginner
    Windows Vista Access 2010 64bit
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    Hallelujah, I found the answer! thanks June7 for putting me on the right path

    Code:
    SELECT  sl1.staff_log_date, sl1.staff_log_empl_num,  (DATEDIFF("s",sl1.staff_log_time, sl2.staff_log_time)/60.00)/60 as  tester, *
    FROM staff_login sl1 INNER JOIN staff_login sl2
    ON sl1.staff_log_empl_num = sl2.staff_log_empl_num
    AND sl1.staff_log_date = sl2.staff_log_date
    WHERE sl1.time_in_time_out = 'IN' and sl2.time_in_time_out = 'OUT';
    I abandoned the idea of restructuring the table. I joined the table to itself then used the datediff function to get the hours

  6. #6
    June7's Avatar
    June7 is online now VIP
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    Glad you figured it out. That is essentially what I suggested but in an all-in-one sql. You seem to catch on fast or you really aren't a newbie. Congratulations!
    How to attach file: http://www.accessforums.net/showthread.php?t=70301 To provide db: copy, remove confidential data, run compact & repair, zip w/Windows Compression.

Please reply to this thread with any new information or opinions.

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